(2x+3)(3x^2-22x+24)=0

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Solution for (2x+3)(3x^2-22x+24)=0 equation: 


Simplifying
(2x + 3)(3x2 + -22x + 24) = 0

Reorder the terms:
(3 + 2x)(3x2 + -22x + 24) = 0

Reorder the terms:
(3 + 2x)(24 + -22x + 3x2) = 0

Multiply (3 + 2x) * (24 + -22x + 3x2)
(3(24 + -22x + 3x2) + 2x * (24 + -22x + 3x2)) = 0
((24 * 3 + -22x * 3 + 3x2 * 3) + 2x * (24 + -22x + 3x2)) = 0
((72 + -66x + 9x2) + 2x * (24 + -22x + 3x2)) = 0
(72 + -66x + 9x2 + (24 * 2x + -22x * 2x + 3x2 * 2x)) = 0
(72 + -66x + 9x2 + (48x + -44x2 + 6x3)) = 0

Reorder the terms:
(72 + -66x + 48x + 9x2 + -44x2 + 6x3) = 0

Combine like terms: -66x + 48x = -18x
(72 + -18x + 9x2 + -44x2 + 6x3) = 0

Combine like terms: 9x2 + -44x2 = -35x2
(72 + -18x + -35x2 + 6x3) = 0

Solving
72 + -18x + -35x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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